asked 13.1k views
4 votes
How do you find the quadratic function with vertex (-2,5) and point (0,9)?

asked
User Mdryden
by
7.3k points

1 Answer

3 votes

Answer: y = (x +2)² + 5

Explanation:

y = a(x - h)² + k where "a" is the leading coefficient and (h, k) is the vertex

Since we don't know "a", we need to plug in the point (x, y) and the vertex (h, k) to solve for "a": (x, y) = (0, 9) and (h, k) = (-2, 5)

y = a(x - h)² + k

9 = a(0 - (-2))² + 5

9 = a(0 + 2)² + 5

9 = a(2)² + 5

-5 -5

4 = a(4)

÷4 ÷4

1 = a

Next, plug in "a" and the vertex (h, k):

y = a(x - h)² + k

y = 1(x +2)² + 5

y = (x +2)² + 5


answered
User Ximyu
by
8.8k points

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