Question

Solve for x x^2 b+t=x^2 e

Answer 1

x^2b + t = x^2e

x^2e - x^2b = t

x^2(e - b) = t

x^2 = t /(e -b)

x = √[t /(e -b)] or x = - √[t /(e -b)]

Answer 2

`x = \sqrt{(t)/((e - b)) }`,
`x = - \sqrt{(t)/((e - b) }`

Explanation:

`x^(2) b + t = x^(2) e`

To solve this equation for x, arrange the like terms together by placing the two terms with variable
`x^(2)` at one side of the equation and the remaining terms at the other side of the equation:

`x^(2) e - x^(2) b = t`

Now take the common terms out and write it as:

`x^(2) (e - b) = t`

`x^(2) = (t)/(e - b)`

Now take square root on both sides:

`\sqrt{x^(2)} = \sqrt{(t)/(e - b)}`

`x = \sqrt{(t)/((e - b))}` ,
`x = - \sqrt{(t)/((e- b))}`