Question

The light produced by the electron in strontium has a wavelength of 608 nm. How much energy must be added to strontium to get it to produce this wavelength

Answer 1

The energy required to produce light of 608 nm from strontium is calculated using the formula E = hc/λ, where E is energy, h is Planck's constant, c is the speed of light, and λ is the wavelength.

Step-by-step explanation:

The question asks how much energy must be added to strontium to produce light with a wavelength of 608 nm. To calculate this, we use the formula E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10-34 J⋅s), c is the speed of light (3.00 x 108 m/s), and λ is the wavelength of the light. Converting 608 nm to meters (608 x 10-9 m), we can calculate the energy per photon. The energy (E) equals:

E = (6.626 x 10-34 J⋅s)(3.00 x 108 m/s) / (608 x 10-9 m)

After calculating, the energy per photon can be found in joules. This value represents the minimum energy that must be added to strontium to emit light of the specified wavelength.

Answer 2

According to Einstein the energy of photon is given by the equation,

E = hν = h . c/λ

where h is Planck's constant, c is the speed of light, ν is the frequency of light and λ is the wavelength of light.

Given, wavelength = 608 nm = 608 x 10⁻⁹ m

Conversion factor: 1 nm = 10⁻⁹ m

c = 3 x 10⁸ m/s

h = 6.626× 10⁻³⁴ J.s

Substituting the data into the equation we get,

E = h . c/λ

E = 6.626× 10⁻³⁴ J.s x (3 x 10⁸ m/s) / 608 x 10⁻⁹ m

E = 3.27 x 10⁻¹⁹J

3.27 x 10⁻¹⁹J energy must be added to strontium to get it to produce 608 nm wavelength.