Question

I need help answering question 4, I’m not sure I how to solve it

Answer 1

I usually skip the calculus but here goes

`\sin y = 5x^4 - 5`

Taking derivatives with respect to x,

`( d (\sin y))/(dx) = ( d(5x^4 - 5))/(dx)`

`\cos y \frac {dy}{dx} = 20 x^3`

`\frac {dy}{dx} = ( 20 x^3)/(\cos y)`

At
`(x,y)=(1,\pi)` we get

`\frac {dy}{dx} = ( 20 (1)^3)/(\cos \pi) = -20`

Answer: -20