asked 229k views
1 vote
The circle x^2+y^2=4 has the point _ as its center

asked
User Shawnzhu
by
7.7k points

2 Answers

1 vote
HEY THERE!!

Compare the above equation with

( {x}^(2) - h)( {y}^(2) - k) = {r}^(2) \\ \\ so \: here \: h = and \: k = 0 \\ so \: the \: centre \: is \: (0 \: 0) \: and \: the \: radius \: is \: 2
Hope it helped you.
answered
User Prash
by
7.7k points
3 votes

Center (0,0)

Radius: 2

answered
User Tono Nam
by
7.6k points

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