Question

Use the method of completing the square to solve x2-8x+7=0

Answer 1

`Solution, solve\:for\:x,\:x^2-8x+7=0\quad :\quad x=7,\:x=1`

Steps:

`Solve\:with\:the\:quadratic\:formula, \mathrm{For\:}\quad a=1,\:b=-8,\:c=7:\quad x_(1,\:2)=(-\left(-8\right)\pm √(\left(-8\right)^2-4\cdot \:1\cdot \:7))/(2\cdot \:1),\\`

`x=(-\left(-8\right)+√(\left(-8\right)^2-4\cdot \:1\cdot \:7))/(2\cdot \:1):\quad 7`

`x=(-\left(-8\right)-√(\left(-8\right)^2-4\cdot \:1\cdot \:7))/(2\cdot \:1):\quad 1`
`\mathrm{The\:final\:solutions\:to\:the\:quadratic\:equation\:are:} x=7,\:x=1`

The correct answer is B.

Answer 2

A should be your answer no 100 %