Question

A proton travels at a speed of 2.0 × 106 meters/second. Its velocity is at right angles with a magnetic field of strength 5.5 × 10-3 tesla. What is the magnitude of the magnetic force on the proton?

A.
1.0 × 10-15 newtons
B.
1.8 × 10-15 newtons
C.
2.1 × 10-16 newtons
D.
5.5 × 10-16 newtons

Answer 1

PLATO ANSWERS!!!!!!!

1.8 × 10^6-15 newtons

Answer 2

The answer is B : F = 1.8 X 10 ∧ -15

Given:

Velocity of the proton: 2.0 × 10∧6 m/sec

Magnetic field strength(B): 5.5 × 10∧-3 tesla

Now it is given that velocity and the magnetic field are at 90 degree.

Also Magnetic force F= qvBsin∅

where F is the magnetic force

q is the charge of the proton which is equal to 1.602x10∧-19 coloumbs

∅ is the angle between the v and B.

v is the velocity of the proton

B is the magnetic field

Substituting the values we get

F = 1.602 x 10 ∧-19 × 2.0 × 10∧6 × 5.5 × 10∧-3 Sin 90

F= 17.6 x 10 ∧-16 N

F= 1.76 x 10∧-15 N

Rounding off we get F = 1.8 X 10 ∧ -15 N