Question

[Precalculus] Find the value of sin(x/2):

Answer 1

Put your number into the half-angle formula and simplify.

`\displaystyle\sin{(\theta)/(2)}=\pm\sqrt{(1-cos(\theta))/(2)}=\sqrt{(1-(1)/(3))/(2)}\\\\=\sqrt{(1)/(3)}=\sqrt{(3)/(9)}\\\\=(√(3))/(3)`

The appropriate selection is ...

`A)\quad(√(3))/(3)`