Question

Question on math please help!

Answer 1

`(3)/(\sqrt6-1)\cdot(\sqrt6+1)/(\sqrt6+1)=(3(\sqrt6+1))/((\sqrt6-1)(\sqrt6+1))=(3\sqrt3+3)/((\sqrt6)^2-1^2)\\\\=(3\sqrt3+3)/(6-1)=(3\sqrt6+3)/(5)\to\boxed{3.}\\\\Used:\\\\(a-b)(a+b)=a^2-b^2\\\\(√(a))^2=a\\\\distributive\ property:\ a(b+c)=ab+ac`