Question

A mixture consists of glucose and water. What is the percent composition of glucose in the mixture if it contains 1.3 moles of glucose (C6H12O6) and the total mass of the mixture is 276 grams?

A. 17.7%
B. 26%
C. 35%
D. 77%
E. 85%

Answer 1

E. 85%

The percent composition of glucose in the mixture is 85%

#platofam

Answer 2

The percent composition of glucose in the mixture is 85 % ( answer E)

Step-by-step explanation

percent composition of glucose = (mass of glucose / mass of the mixture) x 100

Step 1: calculate the mass of glucose ( C6H12O6)

mass of glucose = moles of glucose x molar mass of glucose

molar mass of C6H12O6 = [( 12 x6) + ( 1 x12) + ( 16 x6)= 180 g/mol

mass is therefore= 1.3 moles x 180g/mol = 234 grams

Step 2: calculate the percent composition

= mass of glucose /mass of mixture x 100

= 234 g/276 g x 100 = 85 %(answer E)