Question

Consider the following reaction:

10 KCIO3 + 3 P4 → 3 P4010 + 10 KCI
Given 30 moles of P4 and 86 moles of KCIO3, which would act as the limiting reactant?

Answer 1

Answer:
`KClO_3` is the limiting reactant in the given reaction.

Step-by-step explanation:

Limiting reagent is defined as the chemical specie which gets totally consumed in the reaction and the formation of product is dependent on this reagent.

We are given:

Moles of
`P_4` = 30 moles

Moles of
`KClO_3` = 86 moles

The given chemical equation follows:

`10KCIO_3+3P_4\rightarrow 3P_4O_(10)+10KCI`

By Stoichiometry of the reaction:

If 10 moles of
`KClO_3` reacts with 3 moles of
`P_4`

Then, 86 moles of
`KClO_3` will react with =
`(3)/(10)* 86=25.8moles` of
`P_4`

As, given amount of
`P_4` is more than the required amount. So, it is considered as an excess reagent.

Therefore,
`KClO_3` is considered as a limiting reactant because it limits the formation of product.