The values of 
 satisfying the compound inequality
 satisfying the compound inequality
 are
 are 
![\( x \in \left( -\infty, -(4)/(5) \right]\)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/pzyeyyytcqo5xppaxtfzwhquw3o3enjq58.png) , indicating
 , indicating 
 is less than or equal to
 is less than or equal to 

To find the values of
 that satisfy the compound inequality
 that satisfy the compound inequality 
 you can follow these steps:
you can follow these steps:
1. Isolate the variable 

 
![\[ -22 > -5x - 7 \geq -3 \]](https://img.qammunity.org/2019/formulas/mathematics/middle-school/oee15ptloipvo7onjbw5kibsdx2u7n59fq.png)
 Add 7 to all parts of the compound inequality:
 
![\[ -15 > -5x \geq 4 \]](https://img.qammunity.org/2019/formulas/mathematics/middle-school/sw98xti6kt27gzlsvu1so4nvnj336x0ytd.png)
 Divide all parts by -5. Since you are dividing by a negative number, the direction of the inequality signs will change:
 
![\[ 3 < x \leq -(4)/(5) \]](https://img.qammunity.org/2019/formulas/mathematics/middle-school/7ckth3pv39djqvqyjv38mlwqmodu7vnd2y.png)
2. Write the solution in interval notation:
![\[ x \in \left( -\infty, -(4)/(5) \right] \]](https://img.qammunity.org/2019/formulas/mathematics/middle-school/fpn1fh7e2nrrrrye62x4yyu17qei51rzik.png)
 This indicates that \( x \) can take any value less than or equal to 

So, the answer is
![\( x \in \left( -\infty, -(4)/(5) \right] \).](https://img.qammunity.org/2019/formulas/mathematics/middle-school/hk3awwc0mkirnxp0m3i9hs55psyfiabg8c.png)
The probable question maybe:
What values of x satisfy the compound inequality −22 > −5x − 7 ≥ −3?