Question

Sheila’s age is two years more than twice Nicole’s age. The sum of their ages is the same as Steve’s age. If Steve’s age is ten years less than five times Nicole’s age find the age of each person

Answer 1

Answer : Ages of Nicole , Sheila and Steve will be 6 years , 14 years and 20 years respectively .

Step-by-step explanation:

We have given that ,

Let Nicole's age be x

Let Sheila's age be 2x+2

Let Steve's age = 5x-10

According to question,

Sum of first two ages will be same as the age of Steve's age

So,

i.e.
`x+2x+2=5x-10\\3x+2=5x-2\\12=5x-3x\\12=2x\\6=x`

∴ The age of Nicole will be 6 years

Sheila's age will be 2x+2 = 2×6+2 = 12+2 = 14 years

Steve's age will be 5x-10 = 5×6-10 = 30-10 = 20 years.