Question

Given the function f(x)=x2+2x+1, find:
f(2b)

Answer 1

To calculate f(2b) for the function f(x)=x^2+2x+1, substitute 2b for x, resulting in the simplified form f(2b) = 4b^2 + 4b + 1.

Step-by-step explanation:

To find f(2b) when given the function f(x)=x2+2x+1, you simply substitute 2b for x in the function and then simplify.

The steps are as follows:

1. Substitute x with 2b: f(2b) = (2b)2 + 2(2b) + 1.
2. Square the term 2b: f(2b) = 4b2 + 2(2b) + 1.
3. Multiply 2 by 2b: f(2b) = 4b2 + 4b + 1.

Therefore, the simplified form of f(2b) for the given function is 4b2 + 4b + 1.

Answer 2

f(2b)=(2b)2+2(2b)+1

f(2b)=4b+4b+1

f(2b)=8b+1