asked 140k views
4 votes
How resolve x+1-2- (-x+3)=6-1(1-1)

2 Answers

3 votes


x+1-2-(-x+3)=6-1(1-1)\\\\x+(1-2)-(-x)-(+3)=6-1(0)\\\\x+(-1)+x-3=6-0\\\\x-1+x-3=6\ \ \ \ |\text{use commutative and associative property}\\\\(x+x)+(-1-3)=6\\\\2x-4=6\ \ \ \ |\text{add 4 to both sides}\\\\2x=10\ \ \ \ \ |\text{divide both sides by 2}\\\\\boxed{x=5}

answered
User Arthurr
by
7.9k points
4 votes
x-1+x-3=6-1(0)

2x-4=6

2x=10

x=5
answered
User Francis Cugler
by
7.6k points

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