Question

Suppose an ideal gas is in a container 8.0 l in volume and allowed to expand by having a piston move. The final volume after the piston moves is 16.0 l. If the gas is originally at a pressure of 33,000 pa and a temperature of 300.0 k and the temperature is maintained, what will be the new pressure?

Answer 1

the initial condition is given as -

`p_(1)`=33,000 pa

`v_(1)`=8.0 litre i.e 8×
`10^(-3)`
`m^(3)`

`t_(1)` =300k

final state is given as-

`v_(2) =16 litre` i.e16
`*10^(-3)`
`m^(3)`

`p_(2) =?`

`t_(2)` =300k[the temperature is constant here]

here the temperature is constant.we have to calculate the final pressure

as per the Boyle's law,

`p_(1) *v_(1) =p_(2) *v_(2)`

`p_(2) =(p_(1)*v_(1)  )/(v_(2) )`

=
`(8*10^(-3)*33000 )/(16*10^(-3) )`

=16500 pa [ans]