Question

Solve for x in the equation x2-12x+59=0.

Answer 1

I think it is -5.9. Sorry if I'm wrong.

Answer 2

`(-b+-√(b^2-4ac) )/(2a); ax^2+bx+c \\ \\ a=1, b=-12, c=59`

Use the formulas above to solve the equation.

`1x^2-12x+59=0\\ \\ (-(-12)+-√((-12)^2-4(1)(59)) )/(2(1))\\ \\ (12+-√(144-236) )/(2)\\ \\ (12+-√(-92) )/(2)`

Now this problem will be giving i values since there's a negative in the square root. These i's are known as imaginary numbers. For the answer it should be these two:

x =(12-
`√(-92)`)/2=6-i
`√(23)` = 6.0000-4.7958i

x =(12+
`√(-92)`)/2=6+i
`√(23)` = 6.0000+4.7958i

Let me know if you need help with finding i and all or if you just needed the answer to check your work. Hope this helps!