Question

A right cone has a height of 55 and a slant height of 73. What is the radius of the circular base? Enter your answer as a number, like this: 42

Answer 1

To find the radius of the circular bad, use the Pythagorean thereom.

A^2 + B^2 = C^2

Substitute A^2 with the height, 55, and C^2 with the slant height, 73.

55^2 + B^2 = 73^2

Then simplify

3025 + B^2 = 5329

Subtract 3025 from both sides

B^2 = 2304

Find the square root of both sides

B = 48

The radius of the base of the cone is 48.

If you have any frther questions feel free to ask.

Hope this helps.