Question

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Solve for d.

3+d<3−d



d<−6

d<6
d<−3
d<0

Answer 1

Your first add d to both sides leaving 3+2d <3 . Then you subtract 3 from both sides leaving 2d < 0 then divide bother sides by 2. Leaving you with d < 0!

Answer 2

For this case we have the following inequality:

`3 + d <3-d`

What we must do in this case is to clear the value of "d".

For this, we follow the following steps:

1) We add d on both sides of the inequality:

`3 + d + d <3-d + d`

`3 + 2d <3`

2) We subtract 3 on both sides of the inequality:

`3 + 2d-3 <3-3`

`2d <0`

3) We divide the two sides of the inequality between 2:

`d <0`

Answer:

The result of the inequality is:

`d <0`