Question

How many pounds in a 3.00 l bottle of drinking water?

Answer 1

6.61 Pounds

Solution:

Step 1: Calculate Mass of Water as;

Density = Mass ÷ Volume

Solving for Mass,

Mass = Density × Volume ------ (1)

As,

Density of Water = 1 g.cm⁻³

And,

3 L of Water = 3000 cm³

Putting values in equation 1,

Mass = 1 g.cm⁻³ × 3000 cm³

Mass = 3000 g

Step 2: Convert Grams into Pounds;

As,

1 Gram = 0.002204 Pounds

So,

3000 Grams = X Pounds

Solving for X,

X = (3000 Grams × 0.002204 Pounds) ÷ 1 Gram

X = 6.61 Pounds