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Given the quantities a = 6.1 m, b = 4.1 s, c = 87 m/s, what is the value of the quantity d = a3/(cb2)?

1 Answer

7 votes

It is given in the question that


a = 6.1 m, b = 4.1 s, c = 87 m/s

And the given expression is


d = (a^3)/(cb^2)

Substituting the values of a,b and c, we will get


d = (6.1^3)/(87*4.1^2) = 0.1552m^2/s

So with the given values of a,b and c, we will get


d=0.1552m^2/s

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User Warren  P
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