Question

If 500 ml of mineral oil are used to prepare a liter of mineral oil emulsion, how many grams of the oil, having a specific gravity of 0.87, would be used in the preparation of 1 gallon of the emulsion?

Answer 1

To prepare 1 gallon of the mineral oil emulsion, approximately 0.11484 grams of oil with a specific gravity of 0.87 would be used.

Step-by-step explanation:

To find out how many grams of mineral oil would be used in the preparation of 1 gallon of the emulsion, we need to convert the given volume of 500 ml to gallons. Since 1 gallon is equivalent to 3785 ml, we can divide 500 ml by 3785 ml/gallon to find the volume of the emulsion in gallons. Then, we can use the specific gravity of the oil to calculate the mass of the oil by multiplying the volume in gallons by the specific gravity.

Volume of emulsion in gallons: 500 ml / 3785 ml/gallon = 0.132 gallons

Mass of oil in grams: 0.132 gallons x 0.87 g/ml = 0.11484 grams

Answer 2

We know that

1 gallon = 3.78541 L

1000 ml = 1.0 L

Density = mass / volume

Mass = volume *density

Therefore

(3.78541 L emulsion) x (500 mL oil / 1 L emulsion) x (0.87 g/mL oil) = 1647 g oil

Density = 0.87 g/ ml

Because the density of water = 1.0 g/ ml