Question

A car traveling in a straight line has a velocity of 6.64 m/s at some instant. after 5.55 s, its velocity is 10.9 m/s. what is its average acceleration in this time interval?

Answer 1

We calculate the average acceleration by formula,

`a_(avg)= (v_(i)-v_(f))/(\Delta t)\`

Here vi is initial velocity of the car and after given time its velocity becomes vf .

According to question,

`v_(i) = 6.64 m/s,`

`v_(f) = 10.9m/s`,

`\Delta t =5.55s`

Therefore, putting these values in above equation, we get

a_{avg} = \frac{10.9 m/s - 6.64 m/s}{5.55 s}

[/tex]
`a_(avg)= (4.26 m/s )/(5.55 s) </p><p>`
`a_(avg) = 0.77 m/s^2`}}

Thus, the average acceleration in given time interval is
`0.77 m/s^2`