Question

The compound adrenaline contains 56.7 % c, 6.56 % h, 28.37% o and 8.28 % n by mass. what is the empirical formula for adrenaline?

Answer 1

Answer:- An empirical formula of adrenaline is
`C_8H_1_1O_3N` .

Solution:- Convert given percentages to moles and then calculate the mol ratio to get the simplest whole number ratio of moles of atoms which is the empirical formula of the compound.

`C=(56.7)/(12)` = 4.725 mol

`H=(6.56)/(1)` = 6.56 mol

`O=(28.37)/(16)` = 1.773 mol

`N=(8.28)/(14)` = 0.591 mol

let's calculate the mol ratio now. To calculate the mole ratio, we divide the moles of each by moleso f N as it's the least one:

`C=(4.725)/(0.591)` = 8

`H=(6.56)/(0.591)` = 11

`O=(1.773)/(0.591)` = 3

`N=(0.591)/(0.591)` = 1

So, an empirical formula of adrenaline is
`C_8H_1_1O_3N` .