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The length of a rectangle is 5 cm more than its width. The perimeter is 82 cm. Find the length of the rectangle.

1 Answer

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We will represent the length of the rectangle as
l and the width as
w.


From this problem, we can say
l = w + 5. We can also deduct an equation from the second sentence:


2l + 2w = 82


2(w + 5) + 2w = 82 (from substitution)


2w + 10 + 2w = 82


4w = 72


\boxed{w = 18}


Using this value for
w, we can find
l:


l = 18 + 5


\boxed{l = 23}


The length of the rectangle is 23 cm and the width of the rectangle is 18 cm.

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User Cald
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