Question

An object with a height of 0.3 meter is placed at a distance of 0.4 meter from a concave spherical mirror. An image with a height of 0.1 meter is formed in front of the mirror. How far from the mirror is the image located?

Answer 1

{"version":"1.1","math":"(\frac{h_i}{h_o} =\frac{s_i}{s_o})"}

{"version":"1.1","math":"(\frac{0.1\text{ m}{0.3\text{ m} =\frac{s_i}{0.4\text{ m})"}

Multiply each side of this equation by 0.4.

{"version":"1.1","math":"0.4 \times \left(\frac{0.1}{0.3}=\frac{s_i}{0.4}\right)\times 0.4"}

{"version":"1.1","math":"s_i=\frac{0.4}{0.3}"}

si = 0.133 m

Step-by-step explanation:

Answer 2

We can use the magnification equation for this problem.

Magnification equation:

hi/h0 = di/d0

Where in hi : image size, h0 : object size, di : image distance, d0 : object distance from mirror

So plugging in the given variables we will have the corresponding equation

0.1 m / 0.3 m = di / 0.4 m

di = 0.1333333m

The generated image of the object is located 0.13 meters or 13 cm away from the mirror