Question

Find the quotient of the quantity negative 36 times x to the 3rd power minus 6 times x to the 2nd power plus 12 times x all over negative 6 times x. −36x3 − 6x2 − 2 −6x2 + x − 2 6x2 − x + 2 6x2 + x − 2

Answer 1

`-6x^2+x-2`

Explanation:

`(36x^3-6x^2+12x)/(-6x)`

To divide this,we divide each term by
`-6x`

Apply exponential property

`(a^m)/(^n)=a^(m-n)`

`(36x^3)/(-6x) =-6x^2`

`(-6x^2)/(-6x) =x`

`(12x)/(-6x) =-2`

So the simplified expression is

`-6x^2+x-2`

Answer 2

You can pick the correct answer choice just by looking at the term with the highest degree.

... (36x³)/(-6x) = (-36/6)·(x³/x) = -6x²

The best choice is the second one:

... −6x² + x − 2