Question

A chemist prepares a solution of silver nitrate by measuring out of silver nitrate into a volumetric flask and filling the flask to the mark with water. calculate the concentration in of the chemist's silver nitrate solution. round your answer to significant digits.

Answer 1

Amount of silver nitrate taken = 269.μmol
`AgNO_(3)`

Volume of the solution = 300. mL

Concentration of a solution is generally expressed in terms of molarity. Molarity is defined as the moles of a substance present per liter of the solution.

`Molarity = (Moles of solute)/(Volume of solution(L))`

We want the concentration in millimoles/L.

Converting μmol to millimol solute:

`269.`μ
`mol * (1 millimol)/(1000 micromol)` = 0.269 millimol

Volume from mL to L:
`300. mL * (1 L)/(1000 mL) = 0.300 L`

Therefore concentration of the chemist's solution =
`(0.269 millimol)/(0.300 L) = 0.897 (millimol)/(L)`