Question

Identify the equation of the circle that has its center at (10, 24) and passes through the origin.

Answer 1

Answer: (x−10)2+(y−24)2=676

Step-by-step explanation: it is right

Answer 2

we are given

center=(h,k)=(10,24)

so,

h=10 and k=24

and it passes through origin

so, we can find radius

radius will be distance between (10,24) and (0,0)

`r=√((10-0)^2+(24-0)^2)`

`r=26`

now, we can use standard equation of circle

`(x-h)^2+(y-k)^2=r^2`

so, we will get equation as

`(x-10)^2+(y-24)^2=26^2`..........Answer