Identify the vertex of f(x)= {(x - 5)}^(2) - 3

Question

asked Jul 4, 2019 70.7k views

2 Answers

Eduardo Oliveros · Answer 1 · 2019-07-06T06:55:27+0000

The given equation is in what we know as "vertex form".

In this form, the equation enters the order of
f(x) = a(x - h)^2 + k

, where vertex is
(h,k)

.

In this case, we have
(x-5)

for

and for

we have

. So, the vertex is
(5, -3)

Hendy · Answer 2 · 2019-07-09T18:53:03+0000

If the quadratic is written in the form

y=a(x-h)^(2) +k

then the vertex is the point (h, k).

So from our equation,

f(x)=(x-5)^(2) -3

here on comparing our equation with the vertex form we get ,

h=5 and k=-3

vertex (5,-3)