Question

Simplify this please (m×n)^-1=

Answer 1

We can solve this by using the exponent rule
`a^(-n) = (1)/(a^(n) )`. In this case, a is mn and -n is -1. That means that the simplified version of this is
`(1)/((mn)^(1) )` =
`(1)/((mn))` (anything to the power of one is itself).

Answer 2

`\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^(-n) \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^(-n) \qquad \qquad a^n\implies \cfrac{1}{a^(-n)} \\\\ -------------------------------\\\\ (m* n)^(-1)\implies \cfrac{1}{(m* n)^1}\implies \cfrac{1}{mn}`