Question

A. Find a slope-intercept equation for line A.
b. Find a point-slope for line B.

Answer 1

The slope intercept form of the line is given by:

`y = mx + b`
The point-slope form is given by:

`y-yo = m (x-xo)`
Where,
m: slope of the line
b: cutting point with the y axis
(xo, yo): ordered pair that belongs to the line

For line A:
The slope is

`m = (1-3)/(4-1)`

`m = (-2)/(3)`
The cut point with the y axis is:

`b = (11)/(3)`
Substituting values we have:

`y = -(2)/(3)x + (11)/(3)`

For line B:
The slope is given by:

`m=(1-(-5))/(4-0)`

`m=(1+5)/(4)`

`m=(6)/(4)`

`m=(3)/(2)`
Then, the equation of the line is:

`y-1= (3)/(2)(x-4)`

Answer:
Option A