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What is a postitve root of the equation x^2+5x=150
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What is a postitve root of the equation x^2+5x=150
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Apr 1, 2019
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What is a postitve root of the equation x^2+5x=150
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Maryan
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Two roots, x=10 and x=-15
Positive root: x=10
Check: 10^2 + 5(10) = 150, good
Tamara Koliada
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Apr 2, 2019
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Tamara Koliada
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To solve this equation, we can solve it like it is a quadratic (because it is). To solve it like it's a quadratic, we need to get one side equal to 0. We can do that by subtracting 150 from each side. That gives us x² + 5x -150 = 0. Now, we can factor the equation. Factoring it gives us (x-10)(x+15) = 0. Now, using the zero-product property, we can conclude the the roots for this equation are x = 10, -15. But, since the question is only asking us for the positive root, the answer is
x = 10.
AJN
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Apr 8, 2019
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