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What is a postitve root of the equation x^2+5x=150

asked
User Maryan
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2 Answers

5 votes

x^2 + 5x =150


x^2 + 5x -150 = 0


(x-10)(x+15)= 0

Two roots, x=10 and x=-15

Positive root: x=10

Check: 10^2 + 5(10) = 150, good




answered
User Tamara Koliada
by
8.2k points
5 votes
To solve this equation, we can solve it like it is a quadratic (because it is). To solve it like it's a quadratic, we need to get one side equal to 0. We can do that by subtracting 150 from each side. That gives us x² + 5x -150 = 0. Now, we can factor the equation. Factoring it gives us (x-10)(x+15) = 0. Now, using the zero-product property, we can conclude the the roots for this equation are x = 10, -15. But, since the question is only asking us for the positive root, the answer is x = 10.
answered
User AJN
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7.4k points

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