Please rewrite this system as
y=(1/2)x + 3
y=(3/2)x - 1
Let y = y. Then (1/2)x + 3 = (3/2)x - 1, or 4=x
Subbing 4 for x in the first equation, we get y = (1/2)(4)+3 = 2+3=5
and so the solution is (4,5)
Now go look at the graphs again. Which graph shows 2 lines intersecting at (4,5)?
It's the first set of graphs.