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A stone is thrown vertically upwards with an initial velocity of 40 ms-1. Find the maximum height reached by the stone. What is the net displacement and the total distance cover…

A stone is thrown vertically upwards with an initial velocity of 40 ms-1. Find the maximum height reached by the stone. What is the net displacement and the total distance cover…
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4 votes
A stone is thrown vertically upwards with an initial velocity of 40 ms-1. Find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?

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User Hans Westerbeek
by
8.4k points

1 Answer

4 votes
To find the maximum height we use the expression:
U²=2gh
Where u is the initial velocity,
g is gravitational field strength
h is the maximum height.
h=u²/2g
h=40²/20
=1600/20
=80m
answered
User Bjarki B
by
8.8k points
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