Question

I need help on a mathematics question. I need an explanation.

Solve 2 log x = log 64.

x = 8
x = ±8
x = 32
x = 128
Why is it not B and rather A? I agree with 8, but I also think that -8 works.

Answer 1

Start by dividing both sides by 2 to get
`log(x)= (1)/(2)log(64)`. Doing the math on the right, keeping in mind that logs have an unwritten base of 10, gives us
`log_(10) (x)=.903089987`. Rewriting this in exponential form is
`10^(.903089987)=x`. That means that x = 8. Not negative, only positive.