Answer with Step-by-step explanation:
The equation of a circle having center at (a,b) and radius r is given by:
(x-a)²+(y-b)²=r²
We are given (a,b)=(-2,1)
(x+2)²+(y-1)²=r²
the circle passes through (-4,1)
(-4+2)²+(1-1)²=r²
2²=r²
⇒ r=2
Hence, general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1) is:
(x+2)²+(y-1)²=4