Question

PLEASE HELP!!!!!!!!!

Let x^2+bx+c = 0 be a quadratic whose roots are each two more than the roots of 3x^2-5x-7. What is c?

Answer 1

Let
`x_1 , x_2` be the roots of the equation
`3x^2-5x-7`. By the Viet theorem you have that
`\left \{ {{x_1+x_2=- (5)/(3) } \atop {x_1x_2= (-7)/(3) }} \right.`.

For the equation
`x^2+bx+c = 0` you'll have that
`c=(x_1+2)(x_2+2)=x_1x_2+2(x_1+x_2)+4=(-7)/(3)+2\cdot(- (5)/(3) )+4`
That is
`(-7)/(3)- (10)/(3) +4=- (5)/(3)`.

Answer:
`- (5)/(3)`