Question

Identify an equation in point-slope form for the line perpendicular to y = –2x + 8 that passes through (–3, 9).

Answer 1

For this case we have the following linear equation:

`y = -2x + 8`
As the lines are perpendicular, then the slope of the line is:

`m' = (-1)/(m)`
Where,
m: is the slope of the original line
Substituting values we have:

`m' = (-1)/(-2)`
Rewriting:

`m' = (1)/(2)`
Then, the equation in point-slope form is given by:

`y-yo = m '(x-xo)`
Where,
(xo, yo): ordered pair that goes through the line.
Substituting values we have:

`y-9 = (1)/(2)(x+3)`
Answer:
an equation in point-slope form for the line perpendicular to y = –2x + 8 that passes through (–3, 9) is:

`y-9 = (1)/(2)(x+3)`