When iron rusts in air iron3 oxide is produced. How many moles of oxygen react with 28.0 mol of iron in the rusting reaction 4fe(s) 3o2(g) 2fe2o3(s)

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Nommer · Answer 1 · 2019-09-08T01:42:20+0000

This the balanced equation based on the question
$4Fe + 3O_2 -\ \textgreater \ 2Fe_2O_3$ .

We then proceed with the following calculations

$28.0molFe*(\frac {3molO_2}{4mol Fe})= 21molO_2$

The answer is
is produced.

When iron rusts in air iron3 oxide is produced. How many moles of oxygen react with 28.0 mol of iron in the rusting reaction 4fe(s) 3o2(g) 2fe2o3(s)

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