Question

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Answer 1

`y=mx+b`
m - a slope
b - a y-intercept

`b=-(13)/(3)`
therefore
`y=mx-(13)/(3)`

Put the values of the coordinates of the point (-5; -1) to the equation


`x=-5;\ y=-1\\\\-1=m\cdot(-5)-(13)/(3)\ \ \ |\cdot3\\\\-3=-15m-13\ \ \ |+13\\\\10m=-15\ \ \ |:10\\\\m=(-15)/(10)\\\\m=-(3)/(2)`
Answer:
`y=-(3)/(2)x-(13)/(3)`