Question

Which of the following Gold compounds has the greatest solubility?

Au(OH)3, Ksp = 1 x 10-53
AuCl3, Ksp = 3.2 x 10-25
AuCl, Ksp = 2.0 x 10-13
AuBr3, Ksp = 4.0 x 10-36

Answer 1

AuCl, Ksp = 2.0 x 10-13

Step-by-step explanation:

The Ksp of a substance is the equilibrium constant that shows the solubility of a substance in water. The greater the value of the Ksp, the greater the solubility of the substance in water, the lesser the Ksp, the lesser the solubility of the compound.

AuCl, Ksp = 2.0 x 10-13 has the highest solubility product among the compounds listed. Hence it is the most soluble of all.

Answer 2

AuCl

Step-by-step explanation:

The solubility constant (Ksp) of a compound characterize the solubility in water of a particular substance. The higher the value of the solubility constant (Ksp) the higher the solubility of that compound the water.

For a dissolution process:

`aA_((s))` ⇄
`bB_((aq))` +
`cC_((aq))`

The solubility constant will be:

Ksp ⇄
`[B]^(b)` x
`[C]^(c)`

So the gold compound with the greatest solubility is AuCl with a Ksp = 2.0 x 10⁻¹³.