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Find the area of the triangle ABC given angle A = 60°, b = 2, and c = √2. √3 √6/2 √6 2 to the power of √6
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Find the area of the triangle ABC given angle A = 60°, b = 2, and c = √2. √3 √6/2 √6 2 to the power of √6
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May 3, 2019
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Find the area of the triangle ABC given angle A = 60°, b = 2, and c = √2.
√3
√6/2
√6
2 to the power of √6
Mathematics
high-school
Alex Quintero
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Answer:
6/2
Explanation:
i got this right
JonH
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May 4, 2019
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JonH
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If you know 2 sides and an included angle, the area formula is:
Area = ½ • side 1 • sine (A) • side 2
Area = ½ • 2 * sine (60) * sq root (2)
Area =sine (60) * sq root (2)
The sine of 60 degrees = sq root (3) / 2
Area = sq root (6) / 2
Harpax
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May 10, 2019
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Harpax
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