Question

The specific heat of aluminum is 0.900 j/g•°c. how much heat is required to raise the temperature of a 30.0 g block of aluminum from 25.0°c to 75.0°c?

Answer 1

Q= 1350 joules
Therefore 1350 joules is the heat required.

Answer 2

Answer : The heat required is, 1350 J

Solution :

Formula used :

`Q=m* c* \Delta T=m* c* (T_(final)-T_(initial))`

where,

Q = heat required = ?

m = mass of aluminum = 30 g

c = specific heat of aluminum =
`0.900J/g^oC`

`\Delta T=\text{Change in temperature}`

`T_(final)` = final temperature =
`75^oC`

`T_(initial)` = initial temperature =
`25^oC`

Now put all the given values in the above formula, we get the heat required.

`Q=30g* 0.900J/g^oC* (75-25)^oC`

`Q=1350J`

Therefore, the heat required is, 1350 J