Question

if you could pick the same number twice and the first numbers is odd and less than 5, then the probability that the sum of the two numbers is lessthan 5 is

Answer 1

the 1st number is odd, less than 5, so it might be 1 or 3, the probability is 2/10
But if the sum has to less than 5, than *when 1st number is 1, the second number can only be 1.2.3
and *when 1st number is 3, 2nd can only be 1
*1: 3/100
*2: 1/100
3/100+1/100=4/100
so the answer should be (4/100)/(2/10)=2/10=1/5
I'm not so sure if I'm right
plz tell me if there's something wrong with my answer