asked 102k views
2 votes
How many molecules are in 62.01 grams of CO

1 Answer

2 votes
62.01 g CO x (1 mol CO/ 28 g CO) = 2.2146...

28 g = 12 g (carbon) + 16 g (oxygen)

62.01 has 4 significant figures so the answer would be 2.215
answered
User Remy Kabel
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