Question

A 12 oz can of soda is left in a car on a hot day. In the morning the soda temperature was 60oF with a gauge pressure of 40 psi. What will the gauge pressure be when the soda reaches 90oF (or 363 Kelvin)?

Answer 1

To answer this question, one must be familiar with Gay Lussac's Pressure Temperature Law. According to the law:
`(P1)/(T1) = (P2)/(T2)`

Substituting the values:
Let x be the new gauge pressure.

`(40)/(60) = (x)/(90)`
We get x = 60psi.