asked 156k views
4 votes
A tram moved downward 63 meters in 7 seconds at a constant rate. What was the change in the tram’s elevation each second??

asked
User Iya
by
8.5k points

2 Answers

2 votes

Answer:

9 m/s

Explanation:

To find the change in the tram’s elevation each second, we need to divide the meters by the seconds. To do that, first, set up a fraction;


63 ÷
7 =


(63)/(7) = 9

Therefore, the change in the tram’s elevation each second was 9 m/s

answered
User Bizhan
by
7.7k points
1 vote
You are trying to figure out the rate in which the tram changed elevation. You can figure this out using the information you're given.

You are told that the tram changed elevation by 63 meters in 7 seconds. By dividing the total number of meters traveled, 63, by the number of seconds, 7, you can figure out how many meters the tram traveled each second.

63 \: meters / 7 \: seconds \\ = (63)/(7) \:meters/second\\ = 9 \: m/s

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Answer: The tram changed elevation by 9 meters per second.

answered
User Melchor
by
7.5k points
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