The solubility of gas is 0.58 g/L at a pressure of 104 kPa. What is the solubility if it’s solubility pressure increases to 250 kPa at the same temperature?

Question

asked Sep 23, 2019 177k views

2 Answers

Rococo · Answer 1 · 2019-09-24T01:31:43+0000

Converting to pascal
104/1000=0.104=P1
250/1000=0.25=P2
If 0.58=0.104
=0.25
Cross multiply
Solubility =[0.58*0.25]/0.104=1.39g/l

Trunst · Answer 2 · 2019-09-26T21:34:35+0000

Answer : The solubility of gas at pressure 250 kPa is, 1.39 g/L

Step-by-step explanation:

According top the Henry's Law, the solubility of a gas in a liquid is directly proportional to the pressure of the gas.

$S\propto P$

or,

(S_1)/(S_2)=(P_1)/(P_2)

where,

S_1 = initial solubility of gas = 0.58 g/L

S_2 = final solubility of gas = ?

P_1 = initial pressure of gas = 104 kPa

P_2 = final pressure of gas = 250 kPa

Now put all the given values in the above formula, we get the final solubility of the gas.

(0.58g/L)/(S_2)=(104kPa)/(250kPa)

S_2=1.39g/L

Therefore, the solubility of gas at pressure 250 kPa is, 1.39 g/L